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2024 Australian Open – Wheelchair women's singles

Three-time defending champion Diede de Groot[1] defeated Yui Kamiji in a rematch of the previous year's final, 7–5, 6–4 to win the women's singles wheelchair tennis title at the 2024 Australian Open.[2] It was her sixth Australian Open singles title, her 21st major singles title overall, and her 13th consecutive major singles title.

Seeds

  1. Netherlands Diede de Groot (champion)
  2. Japan Yui Kamiji (final)
  3. Netherlands Jiske Griffioen (semifinals)
  4. Japan Momoko Ohtani (first round, retired)

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 Netherlands Diede de Groot 6 6
United Kingdom Lucy Shuker 3 1 1 Netherlands D de Groot 3 6 6
Argentina María Florencia Moreno 5 2 Netherlands A van Koot 6 1 0
Netherlands Aniek van Koot 7 6 1 Netherlands D de Groot 6 6
3 Netherlands Jiske Griffioen 6 6 3 Netherlands J Griffioen 1 2
Japan Shiori Funamizu 0 4 3 Netherlands J Griffioen 6 6
China Li Xiaohui 3 2 China Z Zhu 3 1
China Zhu Zhenzhen 6 6 1 Netherlands D de Groot 7 6
France Pauline Déroulède 3 2 2 Japan Y Kamiji 5 4
Japan Manami Tanaka 6 6 Japan M Tanaka 2 0
South Africa Kgothatso Montjane 6 2 South Africa K Montjane 6 6
4 Japan Momoko Ohtani 4 0r South Africa K Montjane 1 4
Colombia Angélica Bernal 3 63 2 Japan Y Kamiji 6 6
United States Dana Mathewson 6 77 United States D Mathewson 1 0
Netherlands Lizzy de Greef 0 1 2 Japan Y Kamiji 6 6
2 Japan Yui Kamiji 6 6

References