1989 Virginia Slims of Moscow – Doubles

In the inaugural edition of the tournament, Larisa Savchenko and Natasha Zvereva won the title by defeating Nathalie Herreman and Catherine Suire 6–3, 6–4 in the final.^[1]

	First round							Quarterfinals							Semifinals							Final
	1	L Savchenko N Zvereva	77	77
		C Bakkum M Strandlund	63	64				1	L Savchenko N Zvereva	6	6
		E Brioukhovets J Halard	62	62					E Pampoulova M Pawlik	0	0
		E Pampoulova M Pawlik	77	77											1	L Savchenko N Zvereva	6	6
	3	K Adams K Rinaldi	3	6	5											N Medvedeva L Meskhi	3	4
		N Medvedeva L Meskhi	6	1	7				N Medvedeva L Meskhi	3	6	6
		M Jaggard H Witvoet	6	4	5				L Golarsa S Goleš	6	4	2
		L Golarsa S Goleš	4	6	7																	1	L Savchenko N Zvereva	6	6
	Q	A Khalatian E Maniokova	6	77																		4	N Herreman C Suire	3	4
		D Krajčovičová A Noháčová	1	65				Q	A Khalatian E Maniokova	4	2
		JA Faull R McQuillan	6	3	4			4	N Herreman C Suire	6	6
	4	N Herreman C Suire	4	6	6										4	N Herreman C Suire	6	7
		A Strnadová E Švíglerová	6	1	3											L Field M Van Nostrand	3	5
		T Morton R Stubbs	3	6	6				T Morton R Stubbs	5	60
		L Field M Van Nostrand	77	710					L Field M Van Nostrand	7	77
	2	G Magers B Nagelsen	64	68

• Official results archive (ITF)
• Official results archive (WTA)