1988 Athens Trophy – Singles

Katerina Maleeva was the defending champion but did not compete that year.

Isabel Cueto won in the final 6–0, 6–1 against Laura Golarsa.

A champion seed is indicated in bold text while text in italics indicates the round in which that seed was eliminated.

	First round							Second round							Quarterfinals							Semifinals							Final
	1	I Cueto	6	6
		X Anastasiados	0	0				1	I Cueto	6	6
		I Budařová	6	4	6				I Budařová	0	1
	Q	E Zardo	4	6	3										1	I Cueto	6	6
		J Jonerup	4	4											5	A Kanellopoulou	2	0
		L Corsato	6	6					L Corsato	3	6
		M Jaušovec	2	1				5	A Kanellopoulou	6	7
	5	A Kanellopoulou	6	6																		1	I Cueto	6	6
	3	B Paulus	6	6																		3	B Paulus	2	1
		M-C Calleja	1	3				3	B Paulus	6	7	6
		O Tsarbopoulou	6	6					O Tsarbopoulou	7	5	1
		I Varas	2	1											3	B Paulus	6	6
		A Scott	2	0												S Frankl	2	3
		V Martinek	6	6					V Martinek	4	6	2
		S Frankl	5	5					S Frankl	6	0	6
	7	S Meier	7	2	r																								1	Isabel Cueto	6	6
	8	L Golarsa	7	6																									8	Laura Golarsa	0	1
		A Vieira	6	1				8	L Golarsa	6	6
		R Maršíková	6	3	6				R Maršíková	2	1
		P Medrado	4	6	3										8	L Golarsa	6	6
	Q	S Hack	5	6	6										Q	S Hack	4	2
		S Dalla Valle	7	3	3			Q	S Hack	6	6
		S Loosemore	5	7	2			4	S Goleš	4	3
	4	S Goleš	7	6	6																	8	L Golarsa	6	6
	6	L Garrone	6	5	1/r																	Q	L Lásková	3	1
	Q	L Lásková	4	7	3			Q	L Lásková	4	7	6
		K Quentrec	6	4	3			Q	V Paquet	6	6	2
	Q	V Paquet	3	6	6										Q	L Lásková	6	7
		P Etchemendy	6	6											2	J Wiesner	4	5
		S La Fratta	1	1					P Etchemendy	4	2
	LL	M Pawlik	1	1				2	J Wiesner	6	6
	2	J Wiesner	6	6

• 1988 Athens Trophy Draw