1978 Florida Federal Open – Singles

Virginia Ruzici was the defending champion, but did not compete this year.

Virginia Wade won the title by defeating Anna-Maria Fernandez 6–4, 7–6^(7–1) in the final.^[1]

No seeds were declared for this tournament.

	Semifinals							Final
	Regina Maršíková		6	0	3
	Virginia Wade		2	6	6
								Virginia Wade		6	77
								Anna-Maria Fernandez		4	61
	Wendy Turnbull		6	7	0
	Anna-Maria Fernandez		7	5	6

	First round							Second round							Quarterfinals							Semifinals
		M Navratilova	6	6
		Z Liess	1	3					M Navratilova	6	3	6
		L duPont	1	3					S Margolin	2	6	2
		S Margolin	6	6												M Navratilova	3	6
		R Maršíková	7	6												R Maršíková	6	7
		V Ziegenfuss	5	3					R Maršíková	4	6	6
		B Norton	6	6					B Norton	6	0	1
		A Smith	4	4																			R Maršíková	6	0	3
		V Wade	6	6																			V Wade	2	6	6
		C Stoll	4	1					V Wade	6	6
		B Nagelsen	6	4	3				P Teeguarden	2	1
		P Teeguarden	0	6	6											V Wade	6	7
		K Reid	6	6												K Reid	3	5
		C Meyer	3	4					K Reid	6	6
		P Louie Harper	3	2					B Hallquist	4	2
		B Hallquist	6	6

	First round							Second round							Quarterfinals							Semifinals
		L Antonoplis	4	6	6
		R Gerulaitis	6	2	3				L Antonoplis	6	6	4
		R Blount	6	6					R Blount	7	3	6
		B Stöve	2	2												R Blount	1	6	2
		J DuVall	6	6												W Turnbull	6	3	6
		S Walsh	3	3					J DuVall
		L Forood	1	1					W Turnbull	w/o
		W Turnbull	6	6																			W Turnbull	6	7	0
		B Bunge	6	3	6																		AM Fernandez	7	5	6
		J Evert	4	6	7				J Evert	0	6
		A White	6	6					A White	6	7
		G Coles	2	3												A White	5	5
		AM Fernandez	6	6												AM Fernandez	7	7
		L Hunt	3	1					AM Fernandez	w/o
		Marlie Buehler							E Cawley
		E Cawley	w/o

• Official results archive (ITF)
• Official results archive (WTA)